A stone is thrown in a vertically upward direction with a velocity of 5 ms-1. If the acceleration of the stone during its motion is 10 ms-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

By Ritesh|Updated : November 3rd, 2022

A stone is thrown in a vertically upward direction with a velocity of 5 ms-1. If the acceleration of the stone during its motion is 10 ms-2 in the downward direction, the height attained by the stone will be 1.25 m, and the time taken to reach there is 0.5s.

Step I: It is given that

  • Initial velocity u = 5 ms-1
  • Acceleration = 10 ms-2
  • Final velocity v = 0

Step II: Using the formula we can calculate as:

v2 = u2 + 2as

Now substituting the values we get

0 = 52 + 2 (-10) x s

20s = 25

s = 25/20

On simplifying we get

s = 1.25 m

Thus, 1.25 meters is the maximum height.

Now, consider

v = u + at

On substituting,

0 = 5 + (-10)t

10t = 5

t = 5/10

On simplifying we get

t = 0.5s

As a result, it takes 0.5 seconds to reach the maximum height.

Summary:

A stone is thrown in a vertically upward direction with a velocity of 5 ms-1. If the acceleration of the stone during its motion is 10 ms-2 in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

A stone is flung with a 5 ms-1 velocity in a vertically upward direction. The height the stone will reach is 1.25 m, and the time it takes to get there is 0.5s if the acceleration of the stone during its motion is 10 ms-2 in the downhill direction.

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