A Solution of Concentration Cuso4 is Electrolysed for 965 Sec With a Current of 20a and 50% Efficiency. The Amount of Cu Deposited at Cathode Will Be

By BYJU'S Exam Prep

Updated on: September 25th, 2023

The amount of Cu deposited at cathode will be 6.35 gm.

Given that:

Current (I) = 20A

t = 965 sec

q = 965 x 20C (q = It) (charge = current x time)

Cu²⁺ + 2e^– → Cu (s)

Step 1: To deposit 1 mole of copper, or 63.5 gramme of copper, we need 2 F charge.

2F → 63.5 gm

1F → 63.5gm/ 2F

Step 2:

965 x 20C → (63.5/ 2F x 965 x 20C) gm

(1F = 96500 C)

(63.5/ 2 x 96500 x 965 x 20) gm

= 6.35 gm

Table of content

1. A Solution of Concentration Cuso4 is Electrolysed for 965 Sec With a Current of 20a and 50% Efficiency. The Amount of Cu Deposited at Cathode Will Be

Physical properties of Copper Sulphate

Copper sulphate has molar masses of 159.609 grammes per mole for the anhydrous form and 249.685 grammes per mole for the pentahydrate form.
The pentahydrate of CuSO₄ is vivid blue in colour, in contrast to the anhydrous form’s powdery, grey-white look.
Anhydrous CuSO₄ has an orthorhombic crystal structure whereas CuSO₄.5H₂O crystals have triclinic structures.
The anhydrous and pentahydrate forms have densities of 3.6 grammes per cubic centimetre and 2.286 g.cm^-3
Both hydrated and anhydrous copper sulphates have a tendency to break down when heated, hence they lack precise boiling points.

Hence, the amount of Cu deposited will be 6.35 gm.

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