# A Solution of Concentration Cuso4 is Electrolysed for 965 Sec With a Current of 20a and 50% Efficiency. The Amount of Cu Deposited at Cathode Will Be

By K Balaji|Updated : November 9th, 2022

The amount of Cu deposited at cathode will be 6.35 gm.

Given that:

Current (I) = 20A

t = 965 sec

q = 965 x 20C (q = It) (charge = current x time)

Cu2+ + 2e- → Cu (s)

Step 1: To deposit 1 mole of copper, or 63.5 gramme of copper, we need 2 F charge.

2F → 63.5 gm

1F → 63.5gm/ 2F

Step 2:

965 x 20C → (63.5/ 2F x 965 x 20C) gm

(1F = 96500 C)

(63.5/ 2 x 96500 x 965 x 20) gm

= 6.35 gm

### Physical properties of Copper Sulphate

• Copper sulphate has molar masses of 159.609 grammes per mole for the anhydrous form and 249.685 grammes per mole for the pentahydrate form.
• The pentahydrate of CuSO4 is vivid blue in colour, in contrast to the anhydrous form's powdery, grey-white look.
• Anhydrous CuSO4 has an orthorhombic crystal structure whereas CuSO4.5H2O crystals have triclinic structures.
• The anhydrous and pentahydrate forms have densities of 3.6 grammes per cubic centimetre and 2.286 g.cm-3
• Both hydrated and anhydrous copper sulphates have a tendency to break down when heated, hence they lack precise boiling points.

Hence, the amount of Cu deposited will be 6.35 gm.

Summary:-

## A Solution of Concentration Cuso4 is Electrolysed for 965 Sec With a Current of 20a and 50% Efficiency. The Amount of Cu Deposited at Cathode Will Be

A solution of concentration CuSO4 is electrolysed for 965 sec with a current of 20A and 50% efficiency. The amount of Cu deposited at cathode will be 6.35 gm.

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