A solution contains 25% water, 25% ethanol, and 50% ethanoic acid by mass. Calculate the mole fraction of each component in the same order.

By Ritesh|Updated : November 9th, 2022

(a) 0.301, 0.502, 0.196

(b) 0.502, 0.196, 0.301

(c) 0.245, 0.452, 0.502

(d) 0.502, 0.196, 0.452

The mole fraction of each component in the same order is 0.502, 0.196, and 0.301. Consider the solution's overall mass to be 100 g. A 25 g, 25 g, and 50 g mass of water, ethanol, and ethanoic acid, respectively.

  • Moles of ethanol = 25/46 = 0.543
  • Moles of water = 25/18 = 1.389
  • Moles of ethanoic acid = 50/60 = 0.833

By adding the above three we get:

  • Total moles = 1.389 + 0.543 + 0.833 = 2.765
  • Mole fraction of water = 1.389/2.765 = 0.502
  • Mole fraction of ethanoic acid = 0.833/2.765 = 0.301
  • Mole fraction of ethanol = 0.543/2.765 = 0.196

Benefits of the molar fraction

  • The mole fraction is not temperature-dependent.
  • Calculating the mole fraction does not require knowledge of the phase's density.
  • The mole fraction of an ideal gas mixture is represented by the mixture's partial pressure to total pressure ratio.

Summary:

A solution contains 25% water, 25% ethanol, and 50% ethanoic acid by mass. Calculate the mole fraction of each component in the same order.

A solution contains 25% water, 25% ethanol, and 50% ethanoic acid by mass. The mole fraction of each component in the same order is 0.502, 0.196, 0.301. The mole fraction is the product of the number of molecules of a specific component in a mixture and its total molecular weight. It is a means to convey how concentrated a solution is.

Comments

write a comment

CDS & Defence Exams

CDSCAPFAFCATTA ExamACC ExamOther ExamsPracticePreparation

Follow us for latest updates