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A racing car has a uniform acceleration of 4 ms-2. What distance will it cover in 10s after start?

By BYJU'S Exam Prep

Updated on: September 25th, 2023

A racing car has a uniform acceleration of 4 ms-2. The car will cover a distance of 200 m in 10s after starting. While distance and displacement appear to signify the same thing, they actually have very different definitions and meanings. A scalar quantity known as distance measures “how much ground an object has traversed” while moving. An object’s total change in position is referred to as displacement, a vector variable that measures “how far out of place an object is.” The rate at which velocity changes in relation to time is known as acceleration.

Steps to Calculate the Distance Covered

Step 1: Given that

Time period, t = 10 s

Final acceleration, a = 4 ms-2

The automobile accelerates consistently. This indicates that it was initially at rest.

Initial velocity, u = 0 ms-1

Step 2: Formula used

We know that the second equation of motion is,

s = ut + ½ at2, where s is the distance covered

Step 3: Now we have to calculate the distance covered

By substituting the values in the above equation, we get

s = 0 x 10 + ½ x 4 x 102

s = 200 m

As a result, after starting, the car will travel 200 meters in 10 seconds.

Summary:

A racing car has a uniform acceleration of 4 ms-2. What distance will it cover in 10s after start?

The constant acceleration of a racing car is 4 ms-2. After starting, the vehicle will travel 200 meters in 10 seconds. As both distance and displacement explain the same thing, the actual meaning and definitions are different.

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