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A particle is thrown vertically upwards. Its velocity at half of the height is 10m/s, then the maximum height attained by it will be: (g=10 m/s2)
By BYJU'S Exam Prep
Updated on: September 25th, 2023
(a) 10 m
(b) 20 m
(c) 15 m
(d) 25 m
A particle is thrown vertically upwards. Its velocity at half of the height is 10m/s, then the maximum height attained by it will be 10 m. Steps to find the maximum height attained by the particle is thrown vertically upwards:
Step 1: Given that
The acceleration due to gravity, g = 10 m/s2
Velocity at half of the height, v = 10 m/s
Table of content
Step 2: calculating the equation of motion for a particle at half its height
Let h meters be the maximum height.
The equation of motion formulas allows us to determine:
v2 = u2 – 2gs
where s is the displacement, g is the acceleration caused by gravity, and v is the final velocity.
Substituting the values we get:
102 = u2 – 2g h/2
100 = u2 – gh …. (i)
Step 3: When the particle is at its highest point, find the equation of motion:
v = 0 when the height is greatest.
Substituting the value we get:
0 = u2 – 2gh
u2 = 2gh …. (ii)
Step 4: Using the equations I and (ii), get the maximum height:
The equation I results when the value of u2 is entered.
100 = 2gh – gh
100 = gh
h = 100/g
= 100/10
= 10 m
Summary:
A particle is thrown vertically upwards. Its velocity at half of the height is 10m/s, then the maximum height attained by it will be: (g=10 m/s2)
Vertically upwards, a particle is launched. If the object’s speed at halfway up is 10 m/s, its highest point will be 10 m. The rate at which an object’s position changes in relation to a frame of reference and time is what is meant by velocity.