By solving both the equations
t' = 13t/5
Therefore, the time taken for a similar cup of coffee to cool from 80° C to 60° C at room temperature the same at 20° C is 13t/5.
Summary:
A cup of coffee cools from 90° C to 80° C in t minutes, when the room temperature is 20° C. The time is taken for a similar cup of coffee to cool from 80° C to 60° C at a room temperature same at 20° C is -
5/13 t
13/10 t
13/5 t
10/13 t
A cup of coffee cools from 90° C to 80° C in t minutes, when the room temperature is 20° C. The time taken by a similar cup of coffee to cool from 80° C to 60° C at room temperature the same at 20° C is 13t/5.
Related Questions:-
- A Uniform Rod Of Length 200 Cm And Mass 500 G Is Balanced On A Wedge Placed At 40 Cm Mark A Mass Of 2 Kg Is Suspended From The Rod At 20 Cm And?
- Determine The Current In Each Branch Of The Network Shown In Figure?
- How Can We Find In Which Period And Group In The Periodic Table An Element Exists Explain The Whole Method Thoroughly?
Comments
write a comment