A body starts from rest. What is the ratio of the distance traveled by the body during the 4th and 3rd seconds? (a) 7/5 (b) 5/7 (c) 7/3 (d) 3/7

By Ritesh|Updated : November 9th, 2022

The ratio of the distance traveled by the body during the 4th and 3rd second is 7/5. Steps to calculate the ratio of the distance traveled by the body during the 4th and 3rd seconds:

Given that A body starts from rest

Therefore u = 0

Since we now know that a particle's distance traveled in nth second is written as

Sn = u + a/2 (n - 1)

Ratio of distance traveled in the 4th and 3rd sec

S4th/ S3rd = [0 + a/2 (2 x 4 - 1)]/ [0 + a/2 (2 x 3 - 1)] = (2 x 4 - 1)/ (2 x 3 - 1) = 7/5

The term "displacement" refers to a shift in an object's position. It is a vector quantity with a magnitude and direction. The symbol for it is an arrow pointing from the initial location to the ending place.

While distance and displacement appear to have the same meaning, they actually have very different definitions and implications. Displacement is the measurement of "how far an object is out of place," whereas distance refers to "how much ground an object has covered during its motion."

Summary:

A body starts from rest. What is the ratio of the distance traveled by the body during the 4th and 3rd seconds? (a) 7/5 (b) 5/7 (c) 7/3 (d) 3/7

A body starts from rest. The ratio of the distance traveled by the body during the 4th and 3rd second is 7/5. Distance is the sum of an object's movements, regardless of direction. The distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.

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