A 3.3 kΩ resistor dissipates 0.25 W. The current is

A 3.3 kΩ resistor dissipates 0.25 W. the current is 8.7 mA.

Solution

Power loss in a resistor (P) =I².R

Where, I is the current 

R is the resistance

P is the power loss. Always power loss in a resistor takes place in the form of heat energy.

Given Resistance = 3.3 KΩ

Power loss = 0.25 Watt

0.25=I²×3300  

Current i=√(0.25/3300)=8.7 mA

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