A: 30% solution of H2O2 is marketed as 100 volume hydrogen peroxide. R: 1ml of 30% H2O2 solution will give 100 ml of oxygen at STP. Why is this not the correct explanation?
By BYJU'S Exam Prep
Updated on: September 13th, 2023
Given
A: 30% solution of H2O2 is marketed as 100 volume hydrogen peroxide.
R: 1ml of 30% H2O2 solution will give 100 ml of oxygen at STP.
We know that
2H2O2(I) –> O2(g) + H2O(I)
Here 100 volume solution of H2O2 refers to that 1 L of H2O2 solution will provide 100 L of O2 at STP
2H2O2 –> H2O(I) + O2(g)
68 g 22.4 of O2 at STP
0 g 100 L of O2 at STP
Table of content
Here x g of H2O2 will provide 100 L of O2 at STP
So we get
(68 x 100)/ 22.4 = 303.57 g of H2O2
As strength of H2O2 = 303.57 g/L = 30.357%
Reason –
1ml of 30% H2O2 solution will give 100 ml of oxygen at STP.
So 68g of H2O2 solution will give 22400 ml of oxygen at STP.
0.3 g of H2O2 solution will give 100 ml of oxygen at STP.
The commercially marketed sample is 10V which refers to that the sample has 3% of H2O2.
Therefore, the assertion is correct but the reason is incorrect.
Summary:
A: 30% solution of H2O2 is marketed as 100 volume hydrogen peroxide.
R: 1ml of 30% H2O2 solution will give 100 ml of oxygen at STP. Why is this not the correct explanation?
A: 30% solution of H2O2 is marketed as 100 volume hydrogen peroxide.
R: 1ml of 30% H2O2 solution will give 100 ml of oxygen at STP.
The assertion is correct but the reason is incorrect.
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