A: 30% solution of H2O2 is marketed as 100 volume hydrogen peroxide. R: 1ml of 30% H2O2 solution will give 100 ml of oxygen at STP. Why is this not the correct explanation?

Here x g of H₂O₂ will provide 100 L of O₂ at STP

So we get

(68 x 100)/ 22.4 = 303.57 g of H₂O₂

As strength of H₂O₂ = 303.57 g/L = 30.357%

Reason -

1ml of 30% H₂O₂ solution will give 100 ml of oxygen at STP.

So 68g of H₂O₂ solution will give 22400 ml of oxygen at STP.

0.3 g of H₂O₂ solution will give 100 ml of oxygen at STP.

The commercially marketed sample is 10V which refers to that the sample has 3% of H₂O₂.

Therefore, the assertion is correct but the reason is incorrect.

Summary:

A: 30% solution of H₂O₂ is marketed as 100 volume hydrogen peroxide.

R: 1ml of 30% H₂O₂ solution will give 100 ml of oxygen at STP. Why is this not the correct explanation?

A: 30% solution of H₂O₂ is marketed as 100 volume hydrogen peroxide.

R: 1ml of 30% H₂O₂ solution will give 100 ml of oxygen at STP.

The assertion is correct but the reason is incorrect.

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